15x+25x^2=0

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Solution for 15x+25x^2=0 equation:



15x+25x^2=0
a = 25; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·25·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*25}=\frac{-30}{50} =-3/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*25}=\frac{0}{50} =0 $

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